• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Calculating Maximum Height of a Projectile - Physics Problem
    You're describing a scenario where a ball is thrown upwards and then caught. To solve for the maximum height, we need to use the following steps:

    1. Understand the Physics

    * Free Fall: The ball's motion is governed by gravity.

    * Symmetry: The time it takes to go up to its maximum height is equal to the time it takes to fall back down.

    * Acceleration: The acceleration due to gravity (g) is approximately 9.8 m/s².

    2. Calculate the Time to Reach Maximum Height

    Since the total time is 0.95 seconds and the upward and downward journeys are symmetrical, the time to reach the maximum height is:

    * Time (up) = Time (down) = 0.95 seconds / 2 = 0.475 seconds

    3. Use Kinematics Equation

    We can use the following kinematics equation to relate the time, acceleration, and the initial velocity (which is zero since the ball starts from rest at its highest point) to the maximum height (h):

    * h = v₀ * t + (1/2) * g * t²

    Where:

    * h = maximum height

    * v₀ = initial velocity (0 m/s)

    * t = time to reach maximum height (0.475 s)

    * g = acceleration due to gravity (9.8 m/s²)

    4. Calculate the Maximum Height

    Plugging in the values:

    * h = (0 m/s) * (0.475 s) + (1/2) * (9.8 m/s²) * (0.475 s)²

    * h = 0 + 4.39 m

    Therefore, the maximum height above the hand is approximately 4.39 meters.

    Science Discoveries © www.scienceaq.com