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  • Kinematics Problem: Calculating Distance with Constant Acceleration
    Here's how to solve this problem:

    1. Calculate the acceleration:

    * Force (F) = 6 N

    * Mass (m) = 2 kg

    * Acceleration (a) = F/m = 6 N / 2 kg = 3 m/s² (The acceleration is in the opposite direction of the motion because the force is against it.)

    2. Calculate the initial velocity:

    * Initial velocity (u) = 30 m/s

    3. Calculate the final velocity:

    * Acceleration (a) = -3 m/s² (negative because it's against the motion)

    * Time (t) = 5 s

    * Final velocity (v) = u + at = 30 m/s + (-3 m/s²) * 5 s = 15 m/s

    4. Calculate the distance traveled:

    * Initial velocity (u) = 30 m/s

    * Final velocity (v) = 15 m/s

    * Time (t) = 5 s

    * Distance (s) = (u + v)/2 * t = (30 m/s + 15 m/s) / 2 * 5 s = 112.5 m

    Therefore, the body will move 112.5 meters in 5 seconds after the force is applied.

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