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  • Elastic Collision of Gliders: Calculating Final Velocities
    Here's how to solve this problem using the principles of conservation of momentum and kinetic energy:

    Understanding the Concepts

    * Perfectly Elastic Collision: A collision where both momentum and kinetic energy are conserved.

    * Conservation of Momentum: The total momentum of a system remains constant before and after a collision.

    * Conservation of Kinetic Energy: The total kinetic energy of a system remains constant before and after a collision.

    Let's set up the problem:

    * Mass of each glider: m

    * Initial velocity of glider 1: v₁

    * Initial velocity of glider 2: -v₁ (opposite direction)

    Applying Conservation of Momentum:

    * Initial momentum: mv₁ + m(-v₁) = 0

    * Final momentum: mv₁' + mv₂' = 0 (where v₁' and v₂' are the final velocities)

    Since the initial momentum is zero, the final momentum must also be zero. This gives us:

    v₁' + v₂' = 0

    Applying Conservation of Kinetic Energy:

    * Initial kinetic energy: (1/2)mv₁² + (1/2)m(-v₁)² = mv₁²

    * Final kinetic energy: (1/2)mv₁'² + (1/2)mv₂'²

    Equating initial and final kinetic energy:

    mv₁² = (1/2)mv₁'² + (1/2)mv₂'²

    Solving for Final Velocities:

    1. From the momentum equation: v₁' = -v₂'

    2. Substitute this into the energy equation: mv₁² = (1/2)m(-v₂')² + (1/2)mv₂'²

    3. Simplify: mv₁² = mv₂'²

    4. Solve for v₂': v₂' = v₁

    5. Substitute back into the momentum equation to find v₁': v₁' = -v₁

    Conclusion:

    The final velocities of the two gliders are:

    * Glider 1 (originally moving with velocity v₁): v₁' = -v₁ (The glider reverses direction and maintains its speed)

    * Glider 2 (originally moving with velocity -v₁): v₂' = v₁ (The glider also reverses direction and maintains its speed)

    In a perfectly elastic collision between two objects of equal mass and opposite initial velocities, they simply exchange velocities.

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