Yes, work is done when you apply a force at an angle to the direction of movement, but only the component of the force that acts in the direction of movement contributes to the work. Here's why:

* Work is defined as the force applied multiplied by the distance moved in the direction of the force.

* When the force is at an angle, we need to consider the component of the force that is parallel to the displacement. This component is what actually causes the object to move.

Here's a breakdown:

1. Resolve the Force: The force applied can be broken down into two components:

* Force parallel to displacement (F_parallel): This component is responsible for doing work.

* Force perpendicular to displacement (F_perpendicular): This component does not contribute to work. It might change the direction of motion, but not the distance moved in the direction of the force.

2. Calculate Work: Work is calculated as:

* Work (W) = F_parallel * displacement (d)

Example:

Imagine pushing a box across the floor. You push at an angle, so your force has a component pushing the box forward (parallel to the floor) and a component pushing the box down (perpendicular to the floor). Only the forward component does work, as it causes the box to move.

Key Points:

* Work is a scalar quantity: It has magnitude but no direction.

* Force is a vector quantity: It has both magnitude and direction.

* Work is done only when the force has a component in the direction of displacement.

Let me know if you'd like a visual explanation or more examples!