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  • Wave Velocity in a Cable with Relative Permittivity of 9
    You're asking about the velocity of a travelling wave through a cable with a relative permittivity of 9. Here's how to figure that out:

    Understanding the Relationship

    * Velocity of Light: The speed of light in a vacuum is the fastest speed at which information can travel. We denote it as 'c' and it's approximately 3 x 10^8 meters per second.

    * Permittivity: Permittivity (ε) describes how well a material can store electric energy. Relative permittivity (εr) compares a material's permittivity to that of a vacuum. A higher relative permittivity means the material stores more electric energy.

    * Wave Velocity: The velocity of an electromagnetic wave (like the one travelling through a cable) is affected by the permittivity of the medium.

    The Formula

    The velocity (v) of an electromagnetic wave in a material is given by:

    v = c / √εr

    Calculation

    1. Relative Permittivity: εr = 9

    2. Speed of Light: c = 3 x 10^8 m/s

    3. Calculate Velocity:

    v = (3 x 10^8 m/s) / √9

    v = (3 x 10^8 m/s) / 3

    v = 1 x 10^8 m/s

    Answer

    The velocity of the travelling wave through the cable with a relative permittivity of 9 is 1 x 10^8 meters per second.

    Important Note: This calculation assumes the cable is a perfect dielectric with no losses. In real-world cables, factors like conductor resistance and dielectric losses can slightly reduce the wave velocity.

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