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  • Projectile Motion Problem: Calculating Initial Velocity of a Ball
    Let's break down this problem to find the initial velocity of the ball and other related information.

    Understanding the Physics

    * Gravity: The ball is affected by gravity, which causes it to decelerate as it moves upward. The acceleration due to gravity is approximately -9.8 m/s² (negative since it acts downward).

    * Energy Conservation: We can use the principle of conservation of energy to solve this. The total mechanical energy (potential energy + kinetic energy) of the ball remains constant throughout its motion.

    Calculations

    1. Potential Energy at Maximum Height:

    * The ball's potential energy (PE) at its highest point is: PE = mgh, where:

    * m = mass (0.300 kg)

    * g = acceleration due to gravity (9.8 m/s²)

    * h = height (10.0 m)

    * PE = (0.300 kg)(9.8 m/s²)(10.0 m) = 29.4 J

    2. Kinetic Energy at Release:

    * At the moment of release, the ball has only kinetic energy (KE). Since energy is conserved, the KE at release equals the PE at the highest point: KE = 29.4 J

    3. Initial Velocity:

    * KE = (1/2)mv², where v is the initial velocity.

    * 29.4 J = (1/2)(0.300 kg)v²

    * Solving for v: v = √(2 * 29.4 J / 0.300 kg) ≈ 14.0 m/s

    Therefore:

    * The initial velocity of the ball when it was thrown upward is approximately 14.0 m/s.

    Additional Information

    * Time to Reach Maximum Height: You could also calculate the time it takes for the ball to reach its maximum height using kinematic equations.

    * Total Time in the Air: Since the motion is symmetrical, the total time the ball is in the air is twice the time it takes to reach its maximum height.

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