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  • Calculating Time to Reach 49 m/s for a Falling Object - Physics Explained
    Here's how to solve this problem:

    Understanding the Concepts

    * Acceleration due to gravity (g): 9.8 m/s² means that the velocity of a falling object increases by 9.8 meters per second every second.

    * Initial velocity (v₀): We assume the object starts from rest, so v₀ = 0 m/s.

    * Final velocity (v): We want the object to reach a speed of 49 m/s.

    Using the Equation of Motion

    We can use the following equation of motion:

    v = v₀ + at

    where:

    * v = final velocity (49 m/s)

    * v₀ = initial velocity (0 m/s)

    * a = acceleration due to gravity (9.8 m/s²)

    * t = time (what we want to find)

    Solving for Time (t)

    1. Plug in the values: 49 m/s = 0 m/s + (9.8 m/s²) * t

    2. Simplify: 49 m/s = (9.8 m/s²) * t

    3. Solve for t: t = 49 m/s / 9.8 m/s² = 5 seconds

    Answer: It will take 5 seconds for the object to reach a speed of 49 m/s.

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