Assumptions:
* We'll assume the object starts from rest (initial velocity = 0 m/s).
* We'll use the standard acceleration due to gravity (g) = 9.8 m/s².
Calculations:
1. Final Velocity (v):
* Formula: v = u + at
* v = final velocity
* u = initial velocity (0 m/s)
* a = acceleration due to gravity (9.8 m/s²)
* t = time (2.6 seconds)
* Calculation: v = 0 + (9.8 m/s²) * (2.6 s) = 25.48 m/s
Therefore, the final velocity of the object after 2.6 seconds of freefall is approximately 25.48 m/s.
2. Distance (s):
* Formula: s = ut + (1/2)at²
* s = distance
* u = initial velocity (0 m/s)
* a = acceleration due to gravity (9.8 m/s²)
* t = time (2.6 seconds)
* Calculation: s = (0 m/s) * (2.6 s) + (1/2) * (9.8 m/s²) * (2.6 s)² = 33.124 m
Therefore, the object will fall approximately 33.124 meters in 2.6 seconds.
