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  • Projectile Motion: Calculating Time of Flight for a Launched Arrow
    Here's how to solve this problem using physics:

    Understanding the Problem

    * Free Fall: The arrow is subject to gravity, meaning it accelerates downwards at a rate of approximately 9.8 m/s².

    * Symmetry: The time it takes to go up to its highest point is equal to the time it takes to fall back down.

    Steps to Solve

    1. Find the time to reach the highest point:

    * Use the following kinematic equation: *v_f = v_i + at*

    * *v_f* = final velocity (0 m/s at the highest point)

    * *v_i* = initial velocity (250 m/s)

    * *a* = acceleration due to gravity (-9.8 m/s², negative since it's acting downwards)

    * *t* = time

    * Substitute and solve for *t*:

    * 0 = 250 + (-9.8) * t

    * t = 250 / 9.8 ≈ 25.51 seconds

    2. Double the time to find the total flight time:

    * Total time = 2 * 25.51 seconds ≈ 51.02 seconds

    Therefore, it will take approximately 51.02 seconds for the arrow to hit the ground.

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