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  • Electron Acceleration in Electric Fields: Magnitude & Direction
    Here's how to determine the magnitude and direction of the acceleration of an electron in an electric field:

    1. Understand the Forces Involved

    * Electric Force: An electron, being negatively charged, experiences a force in the *opposite* direction of the electric field. This is because electric fields point in the direction of the force a positive charge would experience.

    * Newton's Second Law: The force on the electron (electric force in this case) causes it to accelerate. We'll use Newton's Second Law (F = ma) to find the acceleration.

    2. Calculate the Magnitude of Acceleration

    * Charge of an electron: e = -1.602 x 10⁻¹⁹ C

    * Electric Field Strength: E = 750 N/C

    * Mass of an electron: m = 9.109 x 10⁻³¹ kg

    Force on the electron:

    F = qE = (-1.602 x 10⁻¹⁹ C)(750 N/C) = -1.2015 x 10⁻¹⁶ N

    Acceleration:

    a = F/m = (-1.2015 x 10⁻¹⁶ N) / (9.109 x 10⁻³¹ kg) ≈ 1.32 x 10¹⁴ m/s²

    3. Determine the Direction

    * Direction of the electric field: The problem states the electric field is 750 NC, but we need to know the direction of this field.

    * Direction of the electron's acceleration: Since the electron has a negative charge, it will accelerate in the opposite direction of the electric field.

    In Summary:

    * The magnitude of the acceleration experienced by the electron is approximately 1.32 x 10¹⁴ m/s².

    * The direction of the acceleration is opposite to the direction of the electric field.

    Important Note: To fully determine the direction of the acceleration, you need to know the direction of the electric field. For example, if the electric field points to the right, the electron will accelerate to the left.

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