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  • Gravity and Radius: Understanding the Inverse Square Law
    The force of gravity at two times the radius is one-fourth the force of gravity at the original radius. Here's why:

    Newton's Law of Universal Gravitation

    The force of gravity between two objects is given by:

    ```

    F = G * (m1 * m2) / r²

    ```

    where:

    * F is the force of gravity

    * G is the gravitational constant

    * m1 and m2 are the masses of the two objects

    * r is the distance between the centers of the two objects

    The Relationship Between Force and Radius

    Notice that the force of gravity is inversely proportional to the square of the distance (r²). This means:

    * If you double the distance (r), the force of gravity becomes 1/2² = 1/4 of the original force.

    * If you triple the distance, the force of gravity becomes 1/3² = 1/9 of the original force.

    In your case:

    You're asking about the force of gravity at twice the radius (2r). Therefore, the force of gravity would be (1/2)² = 1/4 of the original force.

    Example

    If the original force of gravity is 10 Newtons, then at twice the radius, the force of gravity would be 10 * (1/4) = 2.5 Newtons.

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