1. Understand the Problem:

* We're given the initial velocity (36 m/s).

* We're given the acceleration (60g, where 'g' is the acceleration due to gravity, approximately 9.8 m/s²).

* We need to find the distance traveled before coming to a complete stop (final velocity = 0 m/s).

2. Choose the Right Equation:

We can use one of the standard kinematic equations:

* v² = u² + 2as

where:

* v = final velocity (0 m/s)

* u = initial velocity (36 m/s)

* a = acceleration (-60g, since it's deceleration)

* s = distance traveled

3. Convert Acceleration to m/s²:

* a = -60g = -60 * 9.8 m/s² = -588 m/s²

4. Plug in the Values and Solve for 's':

* 0² = 36² + 2 * (-588) * s

* 0 = 1296 - 1176s

* 1176s = 1296

* s = 1296 / 1176

* s ≈ 1.10 meters

Therefore, a person traveling at 36 m/s with a constant deceleration of 60g will come to a complete stop after traveling approximately 1.10 meters.