1. Convert Units:

* Speed: Convert km/hr to m/s:

* 30 km/hr * (1000 m/km) * (1 hr/3600 s) = 8.33 m/s

* 45 km/hr * (1000 m/km) * (1 hr/3600 s) = 12.5 m/s

2. Calculate Acceleration:

* Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)

* a = (12.5 m/s - 8.33 m/s) / 15 s

* a = 0.278 m/s²

3. Calculate Distance:

* Distance (s) = Initial Velocity (u) * Time (t) + (1/2) * Acceleration (a) * Time (t)²

* s = (8.33 m/s * 15 s) + (1/2) * (0.278 m/s²) * (15 s)²

* s = 124.95 m + 31.31 m

* s = 156.26 m

Therefore:

* The train's acceleration is 0.278 m/s².

* The distance traveled by the train is 156.26 meters.