```

Drop = (1/2) * g * (v^2 / (v^2 + r^2))

```

where:

* g = acceleration due to gravity (32.2 ft/s^2)

* v = velocity of the bullet (3000 ft/s)

* r = distance to the target (7500 ft)

Plugging in the numbers, we get:

```

Drop = (1/2) * 32.2 * (3000^2 / (3000^2 + 7500^2))

Drop = 805 ft

```

Therefore, the bullet will drop 805 feet from the line of sight at a distance of 7500 feet.