$$\frac{m v^2}{r} = μ_sn mg \cos\theta$$

$$\frac{(1282\text{ kg}) (25\text{ m/s})^2}{(60\text{ m})} = (μ_s)(1282\text{ kg})(9.8\text{ m/s}^2) (\cos33.7\degree)$$

$$33333\text{ N} = (μ_s)(12601\text{ N})$$

$$μ_s = 2.65$$