$$KE = (1/2)mv^2$$
where:
- KE is the kinetic energy in joules (J)
- m is the mass in kilograms (kg)
- v is the velocity in meters per second (m/s)
Plugging in the given values:
$$KE = (1/2)(50 kg)(80 m/s)^2$$
$$KE = (25 kg)(6400 m^2/s^2)$$
$$KE = 160,000 J$$
Therefore, the kinetic energy of the cannonball will be 160,000 joules.
