Explanations:

Let the acceleration of the plane be \(a\).

Then, we have:

$$v_f=v_i+at$$

$$145=75+15a$$

$$a=4.66\overline{6}\ miles/sec^2$$

Also, the distance traveled by the plane in 15 seconds is:

$$d=\frac{1}{2}(v_i+v_f)t$$

$$=\frac{1}{2}(75+145)(15)$$

$$=2625 miles$$

Therefore, the plane flies 2625 miles in 15 seconds while its velocity is increasing from 75 miles per second to 145 at uniform rate of acceleration.