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  • Average Density of a Coalesced World: Gravitational Contraction
    The answer is:

    $$2.75\rho$$

    Explanation:

    The volume of the combined world is:

    $$V=\frac{4}{3}\pi\left(\frac{3}{4}R\right)^3=\frac{27}{64}\pi R^3$$

    The mass of the combined world is:

    $$M=2M$$

    The average density of the combined world is:

    $$\rho=\frac{M}{V}=\frac{2M}{\frac{27}{64}\pi R^3}=\frac{128}{27}\frac{M}{\pi R^3}=\frac{128}{27}\rho$$

    $$=2.75\rho$$

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