$$h = \frac{1}{2}gt^2$$

where:

- \(h\) is the initial height of the object (\(80\) m)

- \(g\) is the acceleration due to gravity (\(9.8\) m/s²)

- \(t\) is the time taken for the object to hit the ground

Solving for \(t\), we get:

$$t = \sqrt{\frac{2h}{g}}$$

$$t = \sqrt{\frac{2(80)}{9.8}}$$

$$t \approx 4.04$$

Therefore, it will take approximately \(4.04\) seconds for the hammer to hit the ground.