$$F = \frac{Gm_1m_2}{r^2}$$
Where:
- F is the force of gravity in newtons (N)
- G is the gravitational constant (6.674 × 10^-11 N m^2 kg^-2)
- m1 and m2 are the masses of the students in kilograms (kg)
- r is the distance between the students in meters (m)
In this case, we have m1 = m2 = 74 kg and r = 0.85 m. Plugging these values into the equation, we get:
$$F = \frac{(6.674 × 10^-11 N m^2 kg^-2)(74 kg)^2}{(0.85 m)^2}$$
$$F = 6.14 × 10^-9 N$$
Therefore, the force of gravity between the two 74kg students sitting 85 cm apart is approximately 6.14 × 10^-9 N.
