$$v = √(2gh)$$
where:
- v is the final velocity in m/s
- g is the acceleration due to gravity (9.8 m/s²)
- h is the initial height in meters
In this case, the initial height is 100 feet, which is equivalent to 30.48 meters. Plugging this value into the formula, we get:
$$v = √(2 × 9.8 m/s² × 30.48 m)$$
$$v ≈ 24.28 m/s$$
Therefore, the speed of the object when it reaches the ground will be approximately 24.28 m/s, or 54.29 mph.
