$$P = \rho g h$$
Where:
- $$P$$ is the pressure in pascals (Pa)
- $$\rho$$ is the density of the fluid in kilograms per cubic meter (kg/m³)
- $$g$$ is the acceleration due to gravity in meters per second squared (m/s²)
- $$h$$ is the depth in meters (m)
Assuming we are dealing with water at sea level, the density of water is approximately 1000 kg/m³ and the acceleration due to gravity is approximately 9.8 m/s².
Substituting the values into the formula:
$$P = (1000 \text{ kg/m}^3)(9.8 \text{ m/s}^2)(200 \text{ m})$$
$$P = 1,960,000 \text{ Pa}$$
Therefore, the pressure at a depth of 200 feet is approximately 1,960,000 Pa or 1.96 megapascals (MPa).
