f = (1/2π)√(g/L)
where:
- π (pi) is a constant approximately equal to 3.14159
- f is the frequency of the pendulum in vibrations per second (Hertz)
- g is the acceleration due to gravity (approximately 9.8 meters per second squared on Earth)
- L is the length of the pendulum in meters
To use this formula, simply substitute the values of L and g into the formula and calculate the result. The answer will be the frequency of the pendulum's vibrations in Hertz.
For example, if the pendulum has a length of 1 meter and is on Earth, the formula would be:
f = (1/2π)√(9.8/1) ≈ 0.5 Hz
This means that the pendulum will oscillate back and forth (complete one vibration) approximately 0.5 times per second.