$$W = F \times d$$
Where:
- W is the work done in Joules (J)
- F is the force applied in Newtons (N)
- d is the distance moved in meters (m)
In this case, the student applies a force of 45 Newtons (N) to push the chair at a constant speed of 3 meters per second (m/s) for a duration of 6 seconds. The distance moved by the chair can be calculated as:
$$d = v \times t$$
Where:
- v is the velocity in meters per second (m/s)
- t is the time in seconds (s)
Substituting the given values, we get:
$$d = 3 \ m/s \times 6 \ s = 18 \ meters$$
Now we can calculate the work done by the student:
$$W = 45 \ N \times 18 \ m = 810 \ Joules$$
Therefore, the student did 810 Joules of work by applying a force of 45 Newtons to push the chair at a constant speed of 3 meters per second for a duration of 6 seconds.
