Work = force x displacement
In this case, the force is the weight of the basketball, which is given by:
$$W = mg$$
$$W=(0.650\text{ kg})(9.8\text{ m/s}^2)=6.37\text{ N}$$
Where m is the mass of the basketball and g is the acceleration due to gravity.
The displacement is the vertical distance through which the basketball falls, which is:
$$d=h_1−h_2= 6.46\text{ m} − 1.32\text{ m}= 5.14\text{ m}$$
$$d=5.46\text{ m}$$
Therefore, the work done on the basketball by its weight is:
$$W=Fd=(6.37\text{ N})(5.14\text{ m})= 32.78\text{ J}$$
Hence, the work done on the basketball by its weight is $32.78\text{ J}$.
