$$W = Fdcosθ$$
where:
- W is the work done (in Joules)
- F is the force applied (in Newtons)
- d is the displacement (in meters)
- θ is the angle between the force and the displacement
In this case, the force is constant and the displacement is in the same direction as the force, so θ = 0°. Therefore, we can simplify the formula to:
$$W = Fd$$
Substituting the given values, we get:
$$W = (10.0 N)(1.5 m) = 15.0 J$$
Therefore, the work done on the book is 15.0 J.
