The final velocity (v) of an object dropped from a height (h) and accelerating due to gravity (g = 9.8 m/s²) can be calculated using the equation:

v² = u² + 2gh

where:

v is the final velocity of the object (6 m/s)

u is the initial velocity of the object (0 m/s, assuming it is dropped from rest)

g is the acceleration due to gravity (9.8 m/s²)

h is the height from which the object is dropped

To find the value of h, we can rearrange the equation as follows:

h = (v² - u²) / 2g

Substituting the given values:

h = (6² - 0²) / (2 x 9.8)

h = (36 - 0) / 19.6

h = 36 / 19.6

h ≈ 1.84 meters (approximately)

Therefore, the height from which the object was dropped is approximately 1.84 meters.