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  • Solving for Rectangle Length and Width Given Perimeter and Area
    Here's how to solve this problem:

    1. Set up the equations:

    * Let 'l' represent the length of the rectangle.

    * Let 'w' represent the width of the rectangle.

    We know:

    * Perimeter: 2l + 2w = 18

    * Area: l * w = 14

    2. Solve for one variable:

    * From the perimeter equation, we can solve for 'l':

    2l = 18 - 2w

    l = 9 - w

    3. Substitute into the area equation:

    * Substitute the expression for 'l' into the area equation:

    (9 - w) * w = 14

    4. Solve the quadratic equation:

    * Expand the equation: 9w - w² = 14

    * Rearrange into standard quadratic form: w² - 9w + 14 = 0

    * Factor the quadratic: (w - 7)(w - 2) = 0

    * Solve for 'w': w = 7 or w = 2

    5. Find the length:

    * For w = 7: l = 9 - 7 = 2

    * For w = 2: l = 9 - 2 = 7

    Conclusion:

    The rectangle could have the following dimensions:

    * Length = 7 feet, Width = 2 feet

    * Length = 2 feet, Width = 7 feet

    Since a rectangle can be oriented in two ways, both of these solutions are valid.

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