$$\frac{1}{2}mv_1^2=\frac{1}{2}(10 \text{ kg})(4 \text{ m/s})^2=80 \text{ J}$$
The final kinetic energy of the snowboard is:
$$\frac{1}{2}mv_2^2=\frac{1}{2}(10 \text{ kg})(6 \text{ m/s})^2=180 \text{ J}$$
Therefore, the net work done on the snowboard is:
$$W=KE_f-KE_i=180 \text{ J}-80 \text{ J}=\boxed{100 \text{ J}}$$