pOH = -log[OH-]
where [OH-] is the hydroxide ion concentration in moles per liter.
Given that [OH-] = 9.31 x 10-2 M, we can substitute this value into the formula:
pOH = -log(9.31 x 10-2 M)
≈ 1.033
Therefore, the pOH of the solution is approximately 1.033.