$$C_1V_1 = C_2V_2$$
Where:
- C1 is the initial concentration (0.266 M)
- V1 is the initial volume (which we need to find)
- C2 is the final concentration (0.075 M)
- V2 is the final volume (150.0 mL)
Rearranging the formula, we can calculate V1 as follows:
$$V_1 = \frac{C_2V_2}{C_1}$$
Substituting the given values:
$$V_1 = \frac{(0.075 \text{ M})(150.0 \text{ mL})}{0.266 \text{ M}}$$
$$V_1 = 42.86 mL$$
Therefore, 42.86 mL of the 0.266 M LiNO3 solution are required to make 150.0 mL of a 0.075 M solution.
