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  • Horizontal Projectile Motion: Calculating Initial Velocity of a Stone
    Here's how to solve this problem:

    Understanding the Physics

    * Horizontal motion: The stone's horizontal velocity remains constant throughout its flight because there's no horizontal force acting on it (ignoring air resistance).

    * Vertical motion: The stone accelerates downwards due to gravity (g = 9.8 m/s²).

    Calculations

    1. Find the time of flight:

    * We can use the vertical motion to determine the time it takes for the stone to fall 25.00 m.

    * Use the equation: d = v₀t + (1/2)gt² (where d = distance, v₀ = initial vertical velocity = 0, g = acceleration due to gravity, and t = time)

    * Rearranging for time: t = √(2d/g) = √(2 * 25.00 m / 9.8 m/s²) ≈ 2.26 s

    2. Calculate the initial horizontal velocity:

    * We know the horizontal distance traveled (40.00 m) and the time of flight (2.26 s).

    * Use the equation: distance = velocity * time

    * Rearranging for velocity: velocity = distance / time = 40.00 m / 2.26 s ≈ 17.70 m/s

    Answer: The initial horizontal velocity of the stone was approximately 17.70 m/s.

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