Assumptions:
* We're assuming no air resistance for simplicity.
* We'll use the standard acceleration due to gravity (g) as 9.8 m/s².
Calculations:
* Displacement (d):
* The formula for displacement under constant acceleration is: d = v₀t + (1/2)at²
* where:
* d is the displacement
* v₀ is the initial velocity (0 m/s since the rock is dropped from rest)
* t is the time (4 seconds)
* a is the acceleration due to gravity (9.8 m/s²)
* Plugging in the values: d = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²
* Therefore, d = 78.4 meters
* Velocity (v):
* The formula for final velocity under constant acceleration is: v = v₀ + at
* Plugging in the values: v = 0 m/s + (9.8 m/s²)(4 s)
* Therefore, v = 39.2 m/s
Answers:
* The displacement of the rock after 4 seconds is 78.4 meters.
* The velocity of the rock after 4 seconds is 39.2 m/s downwards.
