1. Write the balanced chemical equation for the combustion of propane:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
2. Determine the molar masses of propane (C₃H₈) and oxygen (O₂):
* Propane (C₃H₈): (3 * 12.01 g/mol) + (8 * 1.01 g/mol) = 44.11 g/mol
* Oxygen (O₂): 2 * 16.00 g/mol = 32.00 g/mol
3. Calculate the moles of propane:
* Moles of propane = Mass of propane / Molar mass of propane
* Moles of propane = 100 g / 44.11 g/mol ≈ 2.27 mol
4. Use the mole ratio from the balanced equation to find the moles of oxygen:
* From the equation, 1 mole of propane reacts with 5 moles of oxygen.
* Moles of oxygen = 2.27 mol propane * (5 mol O₂ / 1 mol propane) ≈ 11.35 mol O₂
5. Calculate the mass of oxygen:
* Mass of oxygen = Moles of oxygen * Molar mass of oxygen
* Mass of oxygen = 11.35 mol * 32.00 g/mol ≈ 363.2 g
Therefore, approximately 363.2 grams of oxygen are required to burn 100 grams of propane.
