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  • Kinetic Energy of Water: Calculating Energy at 298K vs. 0°C
    Here's how to determine the difference in average kinetic energy between water at 0°C and 298 K:

    Understanding Kinetic Energy and Temperature

    * Kinetic Energy: The energy of motion. The faster the molecules move, the higher their kinetic energy.

    * Temperature: A measure of the average kinetic energy of the particles in a substance.

    Key Formula:

    The average kinetic energy of an ideal gas is directly proportional to its absolute temperature (in Kelvin):

    ```

    KE = (3/2) * k * T

    ```

    Where:

    * KE = Average kinetic energy

    * k = Boltzmann constant (1.38 × 10^-23 J/K)

    * T = Absolute temperature (in Kelvin)

    Calculations

    1. Convert Temperatures to Kelvin:

    * 0°C = 273.15 K

    * 298 K (already in Kelvin)

    2. Calculate Average Kinetic Energy at Each Temperature:

    * KE (273.15 K) = (3/2) * (1.38 × 10^-23 J/K) * (273.15 K) ≈ 5.65 × 10^-21 J

    * KE (298 K) = (3/2) * (1.38 × 10^-23 J/K) * (298 K) ≈ 6.17 × 10^-21 J

    3. Find the Difference:

    * KE (298 K) - KE (273.15 K) ≈ 6.17 × 10^-21 J - 5.65 × 10^-21 J ≈ 5.2 × 10^-22 J

    Conclusion

    The average kinetic energy of 1 mole of water at 298 K is approximately 5.2 × 10^-22 J higher than at 0°C (273.15 K).

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