* Silver Nitrate (AgNO₃) is the reactant, not the product. You start with silver nitrate and react it with sodium chloride (NaCl).

* The reaction produces silver chloride (AgCl) and sodium nitrate (NaNO₃).

Here's the balanced chemical equation for the reaction:

AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

To answer the question, you need to calculate how much silver chloride (AgCl) is produced, not how much silver nitrate.

To do that, you'd need to use the following steps:

1. Find the moles of AgNO₃:

- Divide the mass of AgNO₃ (4.02 g) by its molar mass (169.87 g/mol).

2. Use the mole ratio from the balanced equation:

- The equation shows a 1:1 mole ratio between AgNO₃ and AgCl. This means the number of moles of AgCl produced is equal to the number of moles of AgNO₃ you started with.

3. Calculate the mass of AgCl produced:

- Multiply the moles of AgCl by its molar mass (143.32 g/mol).

Let me know if you'd like me to walk you through the calculations!