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  • Calculate Vapor Pressure of HgCl₂ Water Solution: Raoult's Law Explained
    Here's how to determine the vapor pressure of a water solution containing HgCl₂ using Raoult's Law:

    Understanding the Concepts

    * Vapor Pressure: The pressure exerted by the vapor of a liquid in equilibrium with its liquid phase.

    * Raoult's Law: States that the partial vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by its mole fraction in the solution.

    * Mole Fraction: The ratio of moles of a component to the total moles in a solution.

    Steps

    1. Identify the Solvent and Solute:

    * Solvent: Water (H₂O)

    * Solute: Mercury(II) chloride (HgCl₂)

    2. Determine the Vapor Pressure of Pure Water:

    * At 25°C, the vapor pressure of pure water is approximately 23.76 torr (you can find this value in a table or online).

    3. Calculate the Mole Fraction of Water:

    * Since the mole fraction of HgCl₂ is 0.163, the mole fraction of water (H₂O) is:

    * Mole fraction of H₂O = 1 - mole fraction of HgCl₂ = 1 - 0.163 = 0.837

    4. Apply Raoult's Law:

    * Vapor pressure of the solution = (Mole fraction of H₂O) * (Vapor pressure of pure H₂O)

    * Vapor pressure of the solution = (0.837) * (23.76 torr)

    * Vapor pressure of the solution ≈ 19.88 torr

    Therefore, the vapor pressure of the water solution containing 0.163 mole fraction HgCl₂ at 25°C is approximately 19.88 torr.

    Important Note:

    * This calculation assumes that HgCl₂ is a non-volatile solute, meaning it doesn't contribute significantly to the vapor pressure of the solution.

    * The actual vapor pressure of the solution might be slightly different due to possible interactions between the solvent and solute molecules.

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