1. Calculate the molar mass of methanol:
* Carbon (C): 12.01 g/mol
* Hydrogen (H): 1.01 g/mol (x 4)
* Oxygen (O): 16.00 g/mol
Molar mass of CH3OH = 12.01 + (1.01 x 4) + 16.00 = 32.05 g/mol
2. Use Avogadro's number to convert molecules to moles:
* Avogadro's number: 6.022 x 10^23 molecules/mol
Moles of CH3OH = (9.03 x 10^24 molecules) / (6.022 x 10^23 molecules/mol) = 15.00 mol
3. Calculate the mass in grams:
Mass of CH3OH = (15.00 mol) x (32.05 g/mol) = 480.75 g
Therefore, the mass of 9.03 x 10^24 methanol molecules is 480.75 grams.
