1. The Ideal Gas Law
The ideal gas law is expressed as:
PV = nRT
Where:
* P is the pressure (in atmospheres, ATM)
* V is the volume (in liters, L)
* n is the number of moles
* R is the ideal gas constant (0.0821 L·atm/mol·K)
* T is the temperature (in Kelvin, K)
2. Solving for Volume (V)
We want to find V, so rearrange the ideal gas law:
V = (nRT) / P
3. Plug in the Values
* n = 2 moles
* R = 0.0821 L·atm/mol·K
* T = 300 K
* P = 1.3 ATM
4. Calculate
V = (2 moles * 0.0821 L·atm/mol·K * 300 K) / 1.3 ATM
V ≈ 38.0 L
Therefore, the volume of oxygen occupied by two moles at 1.3 ATM pressure and 300 K is approximately 38.0 liters.
