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  • Calculate the pH of a 0.15M Calcium Hydroxide Solution: Step-by-Step Guide
    Here's how to calculate the pH of a 0.15 M calcium hydroxide solution:

    1. Understand the Dissociation:

    Calcium hydroxide (Ca(OH)₂) is a strong base. It completely dissociates in water:

    Ca(OH)₂ (aq) → Ca²⁺ (aq) + 2OH⁻ (aq)

    This means that for every 1 mole of Ca(OH)₂ that dissolves, you get 2 moles of hydroxide ions (OH⁻).

    2. Calculate the Hydroxide Ion Concentration:

    * Since the concentration of Ca(OH)₂ is 0.15 M, the concentration of OH⁻ ions is twice that: 0.15 M * 2 = 0.30 M

    3. Calculate the pOH:

    pOH is the negative logarithm of the hydroxide ion concentration:

    pOH = -log[OH⁻] = -log(0.30) ≈ 0.52

    4. Calculate the pH:

    The pH and pOH are related by the following equation:

    pH + pOH = 14

    Therefore:

    pH = 14 - pOH = 14 - 0.52 ≈ 13.48

    Therefore, the pH of a 0.15 M calcium hydroxide solution is approximately 13.48.

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