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  • Calculating HCl Mass for Complete Reaction with Ammonia: A Step-by-Step Guide
    Here's how to calculate the mass of HCl needed to react completely with 0.20 g of ammonia gas (NH₃):

    1. Balanced Chemical Equation:

    The balanced chemical equation for the reaction between ammonia and hydrochloric acid is:

    NH₃(g) + HCl(g) → NH₄Cl(s)

    2. Molar Masses:

    * Molar mass of NH₃ = 14.01 g/mol + 3(1.01 g/mol) = 17.03 g/mol

    * Molar mass of HCl = 1.01 g/mol + 35.45 g/mol = 36.46 g/mol

    3. Stoichiometry:

    The balanced equation shows a 1:1 mole ratio between NH₃ and HCl. This means that for every 1 mole of NH₃, you need 1 mole of HCl to react completely.

    4. Calculate Moles of Ammonia:

    * Moles of NH₃ = (mass of NH₃) / (molar mass of NH₃)

    * Moles of NH₃ = 0.20 g / 17.03 g/mol = 0.0117 mol

    5. Calculate Moles of HCl:

    * Since the mole ratio is 1:1, moles of HCl = moles of NH₃ = 0.0117 mol

    6. Calculate Mass of HCl:

    * Mass of HCl = (moles of HCl) * (molar mass of HCl)

    * Mass of HCl = 0.0117 mol * 36.46 g/mol = 0.43 g

    Therefore, you would need approximately 0.43 grams of HCl to react completely with 0.20 grams of ammonia gas.

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