The balanced equation for the reaction between ethanoic acid (acetic acid) and methanol is:

CH₃COOH + CH₃OH ⇌ CH₃COOCH₃ + H₂O

Here's a breakdown:

* CH₃COOH: Ethanoic acid (acetic acid)

* CH₃OH: Methanol

* CH₃COOCH₃: Methyl acetate (ester product)

* H₂O: Water

This reaction is an esterification reaction, where an acid (ethanoic acid) reacts with an alcohol (methanol) to form an ester (methyl acetate) and water. The reaction is reversible, meaning it can proceed in both directions, depending on the conditions.

Key points to remember:

* This reaction requires an acid catalyst, typically concentrated sulfuric acid (H₂SO₄).

* The reaction is usually carried out under reflux conditions to favor the forward reaction and increase the yield of the ester.

* The reaction is reversible, so to maximize ester formation, you need to remove the water formed during the reaction.