When dibutylamine reacts with HCl, it forms the corresponding dibutylammonium chloride.

Here's the chemical reaction:

(CH3CH2CH2CH2)2NH + HCl → [(CH3CH2CH2CH2)2NH2]Cl

* Dibutylamine ((CH3CH2CH2CH2)2NH) is a secondary amine.

* HCl is a strong acid.

* The reaction is an acid-base reaction where the lone pair on the nitrogen atom in dibutylamine accepts a proton (H+) from HCl.

* This forms a positively charged ammonium ion [(CH3CH2CH2CH2)2NH2]+ and a chloride ion (Cl-), which combine to form dibutylammonium chloride.

Dibutylammonium chloride is a salt that is typically white and solid at room temperature.