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  • Oxygen Required for Reaction with Titanium Chloride: A Step-by-Step Calculation
    Here's how to solve this problem:

    1. Write the Balanced Chemical Equation:

    The reaction between titanium chloride (TiCl₄) and oxygen (O₂) produces titanium dioxide (TiO₂) and chlorine gas (Cl₂). The balanced equation is:

    TiCl₄ + O₂ → TiO₂ + 2Cl₂

    2. Determine the Molar Masses:

    * TiCl₄: 47.87 g/mol (Ti) + 4 * 35.45 g/mol (Cl) = 189.67 g/mol

    * O₂: 2 * 16.00 g/mol = 32.00 g/mol

    3. Calculate Moles of TiCl₄:

    * Moles = mass / molar mass

    * Moles of TiCl₄ = 4.6 g / 189.67 g/mol = 0.0243 mol

    4. Use Mole Ratios from the Balanced Equation:

    The balanced equation shows that 1 mole of TiCl₄ reacts with 1 mole of O₂.

    5. Calculate Moles of O₂ Needed:

    * Since the mole ratio is 1:1, we need 0.0243 moles of O₂.

    6. Calculate Mass of O₂:

    * Mass = moles * molar mass

    * Mass of O₂ = 0.0243 mol * 32.00 g/mol = 0.778 g

    Answer: You need 0.778 grams of oxygen to react with 4.6 grams of titanium chloride.

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