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  • Determine the Empirical Formula of an Oxide from Red Phosphorus Combustion
    Here's how to determine the empirical formula of the oxide:

    1. Determine the mass of oxygen:

    * Mass of oxygen = Mass of oxide - Mass of phosphorus

    * Mass of oxygen = 0.142 g - 0.062 g = 0.080 g

    2. Convert masses to moles:

    * Moles of phosphorus = Mass of phosphorus / Molar mass of phosphorus

    * Moles of phosphorus = 0.062 g / 30.97 g/mol ≈ 0.002 mol

    * Moles of oxygen = Mass of oxygen / Molar mass of oxygen

    * Moles of oxygen = 0.080 g / 16.00 g/mol ≈ 0.005 mol

    3. Find the simplest whole-number ratio of moles:

    * Divide both mole values by the smaller one (0.002 mol):

    * Phosphorus: 0.002 mol / 0.002 mol = 1

    * Oxygen: 0.005 mol / 0.002 mol = 2.5

    4. Adjust to whole numbers (if necessary):

    * Since we have a 1:2.5 ratio, multiply both by 2 to get whole numbers:

    * Phosphorus: 1 * 2 = 2

    * Oxygen: 2.5 * 2 = 5

    5. Write the empirical formula:

    * The empirical formula is P₂O₅.

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