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  • Oxidation States of Na₂Cr₂O₇: A Detailed Explanation
    Here's how to determine the oxidation states of the elements in Na₂Cr₂O₇ (sodium dichromate):

    Rules to Remember

    * Oxygen: Oxygen usually has an oxidation state of -2, except in peroxides (like H₂O₂) where it's -1.

    * Sodium: Sodium is in group 1 of the periodic table, so it always has an oxidation state of +1.

    * The sum of oxidation states in a neutral compound is zero.

    Calculation

    1. Oxygen: We have 7 oxygen atoms, each with an oxidation state of -2, giving a total of -14.

    2. Sodium: We have 2 sodium atoms, each with an oxidation state of +1, giving a total of +2.

    3. Chromium: Let the oxidation state of chromium be 'x'. Since we have two chromium atoms, the total contribution from chromium is 2x.

    Equation:

    +2 + 2x - 14 = 0

    Solving for x:

    2x = 12

    x = +6

    Therefore:

    * Sodium (Na): +1

    * Chromium (Cr): +6

    * Oxygen (O): -2

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