1. Find the molar mass of each element:
* Sodium (Na): 22.99 g/mol
* Bromine (Br): 79.90 g/mol
2. Calculate the molar mass of sodium bromide (NaBr):
* Molar mass of NaBr = 22.99 g/mol + 79.90 g/mol = 102.89 g/mol
3. Calculate the percent composition of each element:
* Percent sodium (Na):
(22.99 g/mol Na / 102.89 g/mol NaBr) x 100% = 22.34%
* Percent bromine (Br):
(79.90 g/mol Br / 102.89 g/mol NaBr) x 100% = 77.66%
Therefore, the percent composition of sodium bromide is:
* Sodium (Na): 22.34%
* Bromine (Br): 77.66%
