Henry's Law

Henry's Law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid. Mathematically:

* S₁/P₁ = S₂/P₂

Where:

* S₁ = Solubility at pressure P₁

* S₂ = Solubility at pressure P₂

Applying Henry's Law

1. Identify the knowns:

* S₁ = 4.0 g/L (solubility at 3.0 ATM)

* P₁ = 3.0 ATM

* P₂ = 1.0 ATM

* S₂ = ? (solubility at 1.0 ATM)

2. Plug the values into Henry's Law equation:

(4.0 g/L) / (3.0 ATM) = S₂ / (1.0 ATM)

3. Solve for S₂:

S₂ = (4.0 g/L * 1.0 ATM) / 3.0 ATM

S₂ = 1.33 g/L (approximately)

Answer:

The solubility of the gas in water when the pressure above is 1.0 ATM is approximately 1.33 g/L.