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  • Formaldehyde Carbon Hybridization: A Detailed Explanation
    Here's a breakdown of the hybridization of bonding orbitals in carbon in formaldehyde (H₂CO):

    1. The Structure of Formaldehyde

    Formaldehyde has a central carbon atom double bonded to an oxygen atom and single bonded to two hydrogen atoms. Its Lewis structure looks like this:

    H

    |

    C = O

    |

    H

    2. Hybridization

    * Carbon's Valence Electrons: Carbon has four valence electrons (2s² 2p²)

    * Hybridization: To form the bonds in formaldehyde, carbon undergoes sp² hybridization. This means:

    * One 2s orbital and two 2p orbitals combine to form three sp² hybrid orbitals. These hybrid orbitals are arranged in a trigonal planar geometry, with bond angles of approximately 120°.

    * The remaining 2p orbital on carbon remains unhybridized.

    3. Bond Formation

    * Sigma Bonds:

    * Two of the sp² hybrid orbitals on carbon form sigma (σ) bonds with the 1s orbitals of the two hydrogen atoms.

    * One of the sp² hybrid orbitals on carbon forms a sigma (σ) bond with the 2p orbital of the oxygen atom.

    * Pi Bond:

    * The unhybridized 2p orbital on carbon overlaps with an unhybridized 2p orbital on oxygen to form a pi (π) bond. This pi bond is responsible for the double bond between carbon and oxygen.

    4. Summary

    In summary, the carbon atom in formaldehyde is sp² hybridized, resulting in:

    * Three sp² hybrid orbitals: Form sigma bonds with the two hydrogen atoms and the oxygen atom.

    * One unhybridized 2p orbital: Forms a pi bond with the oxygen atom.

    This hybridization and bond formation give formaldehyde a planar geometry with bond angles close to 120°.

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