The reaction of barium nitrate (Ba(NO₃)₂) and sodium sulfide (Na₂S) is a double displacement reaction that produces a precipitate. Here's the balanced chemical equation:

Ba(NO₃)₂ (aq) + Na₂S (aq) → BaS (s) + 2NaNO₃ (aq)

Here's a breakdown of the reaction:

* Reactants:

* Barium nitrate (Ba(NO₃)₂) is a soluble ionic compound.

* Sodium sulfide (Na₂S) is also a soluble ionic compound.

* Products:

* Barium sulfide (BaS) is an insoluble ionic compound and will precipitate out of solution as a solid.

* Sodium nitrate (NaNO₃) is a soluble ionic compound and remains in solution.

Observations:

* When you mix solutions of barium nitrate and sodium sulfide, a white precipitate of barium sulfide will form.

* The solution will remain clear after the precipitate settles out.

Net Ionic Equation:

The net ionic equation shows only the species that directly participate in the reaction:

Ba²⁺ (aq) + S²⁻ (aq) → BaS (s)

This equation highlights the formation of the insoluble barium sulfide from the barium and sulfide ions.